Aptitude-2014
Aptitude-2014
A
(A) understanding is the closest in meaning to comprehension.
B
One of his biggest ______ was his ability to forgive
(B) virtues is the most appropriate word to complete the sentence.
D
(D) Rajan had believed that Sajan and he would be working together. can be inferred from the given sentences. Rajan was unhappy that Sajan decided to do the project alone, implying that Rajan expected to work together.
C
To find the tangent, we need to find the derivative of y with respect to x.
dy/dx = 10x
At x = 0, the slope of the tangent (dy/dx) is 0.
A line with a slope of 0 is parallel to the x-axis.
Therefore, the answer is (C) is parallel to the x-axis.
1300
Total cost = Fixed cost + Variable cost
Total cost = 50000 + 800Q
For Q = 100 tons, total cost = 50000 + 800*100 = 130000 Rs
Cost per tonne = Total cost / Quantity = 130000 / 100 = 1300 Rs/tonne
Therefore, the cost of production per tonne for a daily production of 100 tons is 1300 Rs/tonne.
D
ALRVX:
Letter positions in the alphabet: A=1, L=12, R=18, V=22, X=24
Differences between positions: L-A = 11, R-L = 6, V-R = 4, X-V = 2
EPVZB:
Letter positions: E=5, P=16, V=22, Z=26, B=2
Differences between positions: P-E = 11, V-P = 6, Z-V = 4, B-Z = -24 (or 2)
ITZDF:
Letter positions: I=9, T=20, Z=26, D=4, F=6
Differences between positions: T-I = 11, Z-T = 6, D-Z = -22 (or 4), F-D = 2
OYEIK:
Letter positions: O=15, Y=25, E=5, I=9, K=11
Differences between positions: Y-O = 10, E-Y = -20 (or 6), I-E = 4, K-I = 2
From the analysis of the differences between positions:
For ALRVX: Differences are 11, 6, 4, 2
For EPVZB: Differences are 11, 6, 4, 2
For ITZDF: Differences are 11, 6, 4, 2
For OYEIK: Differences are 10, 6, 4, 2
(D) Therefore, the odd one out is OYEIK.
B
Anuj lives on an even-numbered floor (2, 4, or 6)
Bhola does not live on an odd-numbered floor (2, 4, or 6)
Chandan lives above Faisal
Dilip does not live on floor 2
Eswar does not live immediately above or below Bhola
Faisal lives three floors above Dilip
Option A: Anuj (6), Bhola (2), Chandan (5), Dilip (1), Eswar (3), Faisal (4) - This option is not possible as Eswar live immediately above Bhola
Option B: Anuj (2), Bhola (6), Chandan (5), Dilip (1), Eswar (3), Faisal (4) - This option is possible.
Option C: Anuj (4), Bhola (2), Chandan (6), Dilip (3), Eswar (1), Faisal (5) - This option is not possible as Eswar live immediately below Bhola, so this option is incorrect.
Option D: Anuj (2), Bhola (4), Chandan (6), Dilip (1), Eswar (3), Faisal (5) - This option is not possible as Eswar live immediately below Bhola, so this option is incorrect.
Hence option B is correct option
180
Smallest angle of triangle = A
Second largest angle of triangle = B
Largest angle of triangle = C
Smallest angle of quadrilateral = x
Second angle of quadrilateral = y
Third angle of quadrilateral = z
Largest angle of quadrilateral = w
A = (2/3)x
C = 2A
Angles of quadrilateral are in the ratio 3:4:5:6, so x:y:z:w = 3:4:5:6
Let's assume the common factor for quadrilateral angles is 'k'. So, x = 3k, y = 4k, z = 5k, w = 6k
We also know the sum of angles in a quadrilateral is 360 degrees. So,
x + y + z + w = 360 ⇒ 3k + 4k + 5k + 6k = 360 ⇒ k = 20
Hence, x = 3* 20 = 60
From equation 1, A = (2/3) * 60 = 40
From equation 2, C = 2 * 40 = 80
B = 180 - 40 - 80 = 60
Now we can find the required angles:
Second largest angle of triangle = B = 60
Largest angle of quadrilateral = w = 6k = 6*20 = 120
The sum of the second largest angle of the triangle (B) and the largest angle of the quadrilateral (w) is 60 + 120 = 180 degrees.
So, the answer is 180.
D
Let the population of country Y be 'y'.
So, the population of country X is '3y' (since it's thrice the population of Y).
Number of people taller than 6 ft in country X = 1% of 3y = 0.01 * 3y = 0.03y
Number of people taller than 6 ft in country Y = 2% of y = 0.02 * y = 0.02y
Total people taller than 6 ft = People from X + People from Y = 0.03y + 0.02y = 0.05y
Total population = Population of X + Population of Y = 3y + y = 4y
Percentage = (Total people taller than 6 ft / Total population) * 100 = (0.05y / 4y) * 100 = (5 / 400) * 100 = 1.25%
Therefore, the answer is (D) 1.25%.
B
Continuous blue line represents Average rainfall
Dotted line ( red & black ) represent deviation from average value in terms of percentile. 5 to 95 % of date lies between dotted red & black lines.
On average, it rains more in July than in December
True. Because the continuous blue line represents Average rainfall. From graph we can easily deduce
Every year, the amount of rainfall in August is more than that in January
May not true because the graph made from scattered data. Average rainfall was calculated then graph drawn. So its possible in some years that rainfall in January is more than that in August.
July rainfall can be estimated with better confidence than February rainfall
Deviation from average is more February
In August, there is at least 500 mm of rainfall
May not true because the graph made from scattered data. Average rainfall was calculated then graph drawn. So its possible in some years that rainfall in August is lower than 500 mm.
Hence option (B) is correct