The bacteria in milk are destroyed when it is  heated to 80 degree Celsius.

Tampering with someone else’s email account is now a very serious offence.

the action of touching or making changes to something that you 

should not, usually when you are trying to damage it or do something illegal

Cricket : Ball Tampering

• The volume of a cone is given by V = (1/3)πr²h, where r is the radius and h is the height.

• If the radius is increased by 50%, the new radius becomes 1.5r.

• The new volume V' = (1/3)π(1.5r)²h = (1/3)π(2.25r²)h = 2.25V.

• The increase in volume is V' - V = 2.25V - V = 1.25V.

• This represents a 125% increase in volume.

Therefore, the correct answer is (C) 125%.

1. Mode: Since x appears three times, it is the mode.= x

2. Median: The median is the middle value, which is y. Median = y

3. Mean: Mean = (1 + 3x + 2y + 9 + 16 + 18) / 9

Given that Mean = Median = 2 * Mode:

• y = 2x

• (44 + 3x + 2y ) / 9 = 2x

Substitute y = 2x in the second equation:

• (7x + 44) / 9 = 2x

• 11x = 44

• x = 4

Since y = 2x, then y = 2 * 4 = 8.

Therefore, the value of y is 8.

So, the answer is (D) 8.

(B) metro construction has to be done carefully considering its impact on the foundations of

existing buildings.

First Amar will be allotted room R as per his preference

Then Akbar will be allotted room S as his first preference is already occupied by Amar

Anthony will get P

Finally Amar will get his first preference Q

So, the answer is (B) 

To find the last digit of a large number raised to a power, we only need to consider the last digit of the base number.

Last digit of (2171)^7:

• The last digit of 2171 is 1.

• Any power of 1 will always be 1.

Last digit of (2172)^9:

• Let's observe the powers of 2: 

             2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16 (last digit is 6), 2^5 = 32 (last digit is 2).

• We can see a pattern: the last digits repeat in a cycle of 4 (2, 4, 8, 6).

• Since 9 divided by 4 leaves a remainder of 1, the last digit of (2172)^9 is the same as the last digit of 2^1, which is 2.

Last digit of (2173)^11:

• Let's observe the powers of 3: 

3^1 = 3, 3^2 = 9, 3^3 = 27 (last digit is 7), 3^4 = 81 (last digit is 1), 3^5 = 243 (last digit is 3).

• We can see a pattern: the last digits repeat in a cycle of 4 (3, 9, 7, 1).

• Since 11 divided by 4 leaves a remainder of 3, the last digit of (2173)^11 is the same as the last digit of 3^3, which is 7.

Last digit of (2174)^13:

• Let's observe the powers of 4:

 4^1 = 4, 4^2 = 16 (last digit is 6), 4^3 = 64 (last digit is 4), 4^4 = 256 (last digit is 6).

• We can see a pattern: the last digits repeat in a cycle of 2 (4, 6).

• Since 13 divided by 2 leaves a remainder of 1, the last digit of (2174)^13 is the same as the last digit of 4^1, which is 4.

Now, we need to find the last digit of 1 + 2 + 7 + 4 = 14.

Therefore, the last digit of the given expression is 4.

So, the answer is (B) 4.

• Jobs: P, Q, R, S

• Time for each job: P - 30 mins, Q - 20 mins, R - 60 mins, S - 15 mins

• Number of objects for each job: P - 2, Q - 3, R - 1, S - 4

• Total objects: 10

To minimize the total time, we need to distribute the jobs evenly between the two machines, maximizing their utilization.

Time taken for each job type:

• Job P: 2 objects * 30 mins/object = 60 mins

• Job Q: 3 objects * 20 mins/object = 60 mins

• Job R: 1 object * 60 mins/object = 60 mins

• Job S: 4 objects * 15 mins/object = 60 mins

Observation:

• Each job type takes exactly 60 minutes to complete for all its objects.

Distribution:

• We can divide the jobs equally between the two machines.

• Each machine will spend 60 minutes on each job type.

Total time for each machine:

• 60 mins (Job P) + 60 mins (Job Q) + 60 mins (Job R) + 60 mins (Job S) = 240 mins

Since there are two machines, the total time to complete all jobs is 240 mins / 2 = 120 mins.

Therefore, the minimum time needed to complete all the jobs is 120 minutes or 2 hours.