GATE-2017
GATE-2017
1
solution
2.99 to 3.01
solution
3
solution
C
solution
C
solution
C
solution
D
solution
B
solution
A
solution
D
solution
0.52 to 0.56
solution
B
solution
298 to 302
solution
D
solution
119 to 121
solution
B
solution
A
solution
B
solution
C
solution
C
solution
A
solution
15900 to 16100
solution
B
solution
B
solution
A
solution
0.49 to 0.51
solution
B
solution
D
solution
0.35 to 0.37
solution
198 to 202
solution
0.59 to 0.61
solution
2440 to 2460
solution
0.90 to 0.92
solution
14.7 to 15.1
solution
0.30 to 0.33
solution
C
solution
9.9 to 10.1
solution
12.99 to 13.01
solution
C
solution
C
solution
B
solution
0.86 to 0.90
solution
B
solution
3.9 to 4.1
solution
13.0 to 13.5
solution
1.0 to 1.0
solution
0.79 to 0.81
solution
20.2 to 20.6
solution
3.9 to 4.1
solution
0.36 to 0.38
solution
0.77 to 0.80
solution
10
solution
16300 to 16600
solution
90.0 to 93.0
solution
A
solution
C
solution
The bacteria in milk are destroyed when it is heated to 80 degree Celsius.
D
solution
C
solution
The volume of a cone is given by V = (1/3)πr²h, where r is the radius and h is the height.
If the radius is increased by 50%, the new radius becomes 1.5r.
The new volume V' = (1/3)π(1.5r)²h = (1/3)π(2.25r²)h = 2.25V.
The increase in volume is V' - V = 2.25V - V = 1.25V.
This represents a 125% increase in volume.
Therefore, the correct answer is (C) 125%.
D
solution
Mode: Since x appears three times, it is the mode.= x
Median: The median is the middle value, which is y. Median = y
Mean: Mean = (1 + 3x + 2y + 9 + 16 + 18) / 9
Given that Mean = Median = 2 * Mode:
y = 2x
(44 + 3x + 2y ) / 9 = 2x
Substitute y = 2x in the second equation:
(7x + 44) / 9 = 2x
11x = 44
x = 4
Since y = 2x, then y = 2 * 4 = 8.
Therefore, the value of y is 8.
So, the answer is (D) 8.
B
solution
(B) metro construction has to be done carefully considering its impact on the foundations of
existing buildings.
B
solution
First Amar will be allotted room R as per his preference
Then Akbar will be allotted room S as his first preference is already occupied by Amar
Anthony will get P
Finally Amar will get his first preference Q
So, the answer is (B)
B
solution
To find the last digit of a large number raised to a power, we only need to consider the last digit of the base number.
Last digit of (2171)^7:
The last digit of 2171 is 1.
Any power of 1 will always be 1.
Last digit of (2172)^9:
Let's observe the powers of 2:
2^1 = 2, 2^2 = 4, 2^3 = 8, 2^4 = 16 (last digit is 6), 2^5 = 32 (last digit is 2).
We can see a pattern: the last digits repeat in a cycle of 4 (2, 4, 8, 6).
Since 9 divided by 4 leaves a remainder of 1, the last digit of (2172)^9 is the same as the last digit of 2^1, which is 2.
Last digit of (2173)^11:
Let's observe the powers of 3:
3^1 = 3, 3^2 = 9, 3^3 = 27 (last digit is 7), 3^4 = 81 (last digit is 1), 3^5 = 243 (last digit is 3).
We can see a pattern: the last digits repeat in a cycle of 4 (3, 9, 7, 1).
Since 11 divided by 4 leaves a remainder of 3, the last digit of (2173)^11 is the same as the last digit of 3^3, which is 7.
Last digit of (2174)^13:
Let's observe the powers of 4:
4^1 = 4, 4^2 = 16 (last digit is 6), 4^3 = 64 (last digit is 4), 4^4 = 256 (last digit is 6).
We can see a pattern: the last digits repeat in a cycle of 2 (4, 6).
Since 13 divided by 2 leaves a remainder of 1, the last digit of (2174)^13 is the same as the last digit of 4^1, which is 4.
Now, we need to find the last digit of 1 + 2 + 7 + 4 = 14.
Therefore, the last digit of the given expression is 4.
So, the answer is (B) 4.
A
solution
Jobs: P, Q, R, S
Time for each job: P - 30 mins, Q - 20 mins, R - 60 mins, S - 15 mins
Number of objects for each job: P - 2, Q - 3, R - 1, S - 4
Total objects: 10
To minimize the total time, we need to distribute the jobs evenly between the two machines, maximizing their utilization.
Time taken for each job type:
Job P: 2 objects * 30 mins/object = 60 mins
Job Q: 3 objects * 20 mins/object = 60 mins
Job R: 1 object * 60 mins/object = 60 mins
Job S: 4 objects * 15 mins/object = 60 mins
Observation:
Each job type takes exactly 60 minutes to complete for all its objects.
Distribution:
We can divide the jobs equally between the two machines.
Each machine will spend 60 minutes on each job type.
Total time for each machine:
60 mins (Job P) + 60 mins (Job Q) + 60 mins (Job R) + 60 mins (Job S) = 240 mins
Since there are two machines, the total time to complete all jobs is 240 mins / 2 = 120 mins.
Therefore, the minimum time needed to complete all the jobs is 120 minutes or 2 hours.
C
solution